The answer
Because the method is detached from obj when passed as a reference. setTimeout calls it with this as the global object (or undefined in strict mode). Fix it with .bind(obj), an arrow wrapper, or () => obj.method().
Common Function Bugs in JavaScript and How to Fix Them
Why does setTimeout(obj.method, 0) lose this in JavaScript?
More FAQs in Common Function Bugs in JavaScript and How to Fix Them
Use let instead of var so each iteration gets a fresh binding, or wrap the body in an IIFE that captures the current value of i as a parameter.
Because the braces are interpreted as a block body, and the object literal looks like a label statement. Wrapping the object in parentheses (n) => ({ x: 1 }) makes it an expression body that returns the object.
Because arrays are passed by reference. Mutating the parameter mutates the same object the caller holds. Copy the array ([...list]) before mutating if you want to preserve the original.
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