The answer
It halves the number of operations (N/2), but because we drop constants in Big O, it is still considered O(N) linear time.
It halves the number of operations (N/2), but because we drop constants in Big O, it is still considered O(N) linear time.
If the loop iterates from 0 to N incrementing by 1, the time complexity is strictly O(N) Linear Time.
No. Big O measures the worst-case scenario. Even if you break early in the best case, the worst case still requires checking all N elements, so it remains O(N).
O(N) + O(N) = O(2N). However, in Big O notation, we drop constants, so the final time complexity is still O(N).
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